{"id":187803,"date":"2023-04-10T11:06:48","date_gmt":"2023-04-10T15:06:48","guid":{"rendered":"https:\/\/ibkrcampus.com\/?p=187803"},"modified":"2023-04-19T15:37:47","modified_gmt":"2023-04-19T19:37:47","slug":"all-about-python-sets","status":"publish","type":"post","link":"https:\/\/www.interactivebrokers.com\/campus\/ibkr-quant-news\/all-about-python-sets\/","title":{"rendered":"All about Python Sets"},"content":{"rendered":"\n

Background on sets<\/strong><\/h2>\n\n\n\n

A set in Python<\/a> is an unordered collection of unique elements. Sets are mutable<\/strong> and iterable<\/strong> (more on these properties later). Sets are useful for when dealing with a unique collection of elements \u2013 e.g. finding the unique elements within a list to determine if there are any values which should be present. The operations built around sets are also handy when you need to perform mathematical set-like operations. For example, how would you figure out the common elements between two lists<\/a>? Or what elements are in one list, but not another? With sets, it\u2019s easy!<\/p>\n\n\n\n

How to create a set<\/strong><\/h2>\n\n\n\n

We can define a set using curly braces, similar to how we define dictionaries.<\/p>\n\n\n\n

nums = {10, 20, 30, 40, 50}<\/pre>\n\n\n\n
We can confirm that nums<\/strong> is indeed a set by using the type<\/strong> function:<\/p>\n\n\n\n
type(nums)<\/pre>\n\n\n\n
We can also convert a list to a set like this:<\/p>\n\n\n\n
some_list = [1, 2, 3, 4, 5]\n \nsome_set = set(some_list)<\/pre>\n\n\n\n
By wrapping our list inside set<\/em>, we can coerce our list into a set. Also, since sets contain only unique elements (e.g. no duplicates), if we convert a list containing duplicate values to a set, the set will give us just the unique elements.<\/p>\n\n\n\n
dup_values = [3, 4, 4, 4, 3, 3, 3, 4, 4, 5]\n \nset(dup_values)<\/pre>\n\n\n\n
\"\"<\/figure>\n\n\n\n
How to test if two sets are equal<\/strong><\/h2>\n\n\n\n
We can test if two sets are equal using the normal \u201c==\u201d operator.<\/p>\n\n\n\n
other_nums = {30, 10, 50, 40, 20}\n \nother_nums == nums # returns True\n \nnums == {20, 30} # returns False<\/pre>\n\n\n\n
Notice \u2013 since sets are unordered, it doesn\u2019t matter that the set other_nums<\/em> looks like its elements are in a different order. Set equality comparison just takes into account if the two sets share the exact same elements, regardless of order. And that brings us to the next point \u2013 there\u2019s no indexing with sets. This means there\u2019s no such thing as the \u201cfirst\u201d element or \u201csecond element\u201d, etc. in a set (unlike a list). Each set is a just a container of unique, unordered<\/em> elements.<\/p>\n\n\n\n
Combining sets<\/strong><\/h2>\n\n\n\n
To combine, or take the union of sets, we use the union<\/strong> method:<\/p>\n\n\n\n
others = {60, 70, 80}\n \ncombined = nums.union(others)<\/pre>\n\n\n\n
\"\"<\/figure>\n\n\n\n
Adding elements to sets<\/strong><\/h2>\n\n\n\n
To add an element (or elements) to a set, we use the add<\/strong> method.<\/p>\n\n\n\n
# add 60 to nums set\nnums.add(60)\n \n# add 70 to nums set\nnums.add(70)<\/pre>\n\n\n\n
\"\"<\/figure>\n\n\n\n
Getting the intersection of two sets<\/strong><\/h2>\n\n\n\n
To get the intersection, or what common elements exist between two sets, we use the intersection<\/strong> method.<\/p>\n\n\n\n
nums.intersection(others)<\/pre>\n\n\n\n
\"\"<\/figure>\n\n\n\n
Now, what if we want to find the common elements between two lists, rather than sets? All we have to do is convert our lists to sets, and we can use the same intersection<\/strong> method.<\/p>\n\n\n\n
list1 = [4, 5, 5, 6, 7]\nlist2 = [5, 7, 8]\n \nset(list).intersection(set(list2)) # returns {5, 7}<\/pre>\n\n\n\n
How to get the difference between two sets<\/strong><\/p>\n\n\n\n
We can get the difference between two sets (i.e. what elements exist in one set, but not the other) using the difference<\/strong> method.<\/p>\n\n\n\n
nums.difference(others)<\/pre>\n\n\n\n
\"\"<\/figure>\n\n\n\n
Just like getting finding the common elements between lists with the intersection<\/strong> method, we can find what elements belong in one list, but not another by converting the lists into sets and applying the difference<\/strong> method. For example, the below code will return {1, 2} because 1 and 2 are each present in list1, but not list2.<\/p>\n\n\n\n
list1 = [1, 2, 3, 4]\nlist2 = [3, 4, 5]\n \nset(list1).difference(set(list2)) # returns {1, 2}<\/pre>\n\n\n\n
How to get the symmetric difference between two sets<\/strong><\/h2>\n\n\n\n
The symmetric difference between two sets, A and B, are the set of elements that exist only in A, or only in B. We can illustrate with our example sets.<\/p>\n\n\n\n
nums.symmetric_difference(others)<\/pre>\n\n\n\n
\"\"<\/figure>\n\n\n\n
Adding a set of elements to another set<\/strong><\/h2>\n\n\n\n
<\/strong><\/p>\n\n\n\n
Using the add<\/strong> method above, we can add one element at a time to a set. But what if we want to add a full set of other elements at once? We can do that using the update<\/strong> method. This method is inplace<\/strong>, which means we don\u2019t need to assign a variable to the new result. Instead, calling nums.update(SOME SET GOES HERE)<\/strong> will update the value of nums<\/strong> to include whatever elements are in the input set. We can see this in the example below by updating nums<\/strong> to include the elements in the letters<\/strong> set that we define.<\/p>\n\n\n\n
letters = {\"a\", \"b\", \"c\"}\n \nnums.update(letters)<\/pre>\n\n\n\n
\"\"<\/figure>\n\n\n\n
If we want to take out these new elements, we can just use the previously mentioned difference<\/strong> method.<\/p>\n\n\n\n
nums = nums.difference(letters)<\/pre>\n\n\n\n
How to tell if two sets contain no common elements (disjoint)<\/strong><\/h2>\n\n\n\n
Python has several Boolean methods available for sets. For instance, we can check if two sets are disjoint (i.e. they do not share any common elements) by using the isdisjoint<\/strong> method.<\/p>\n\n\n\n
nums.isdisjoint(letters) # returns True<\/pre>\n\n\n\n
\"\"<\/figure>\n\n\n\n
{\"a\", \"d\"}.isdisjoint(letters) # returns False<\/pre>\n\n\n\n
Checking if a set is a subset of another<\/strong><\/p>\n\n\n\n
sample = {\"a\", \"c\"}\n \nsample.issubset(letters) # returns True\n \nsample.issubset(nums) # returns False<\/pre>\n\n\n\n
\"\"<\/figure>\n\n\n\n
Checking if a set is a super set of another<\/strong><\/h2>\n\n\n\n
Similarly, we can also test if a set is a super set of another (i.e. A is a super set of B if every element in B is also in A, which also means that B must be a subset of A). In this case we use the superset<\/strong> method.<\/p>\n\n\n\n
sample = {\"a\", \"c\"}\n \nletters.issuperset(sample) # returns True\n \nletters.issuperset(nums) # returns False<\/pre>\n\n\n\n
\"\"<\/figure>\n\n\n\n
How to remove a single element from a set<\/strong><\/h2>\n\n\n\n
Removing a single element from a set can be done a couple of ways. One way is using the discard<\/strong> method. This method will not<\/em> raise an error if the element to be removed is not actually present in the set. The discard<\/strong> method is inplace.<\/p>\n\n\n\n
mixture = {\"a\", \"b\", 1, 2, 3}\n \n# after running this line\n# mixture no longer contains \"a\"\nmixture.discard(\"a\")\n \n# nothing happens to mixture\n# since the string \"something\" is not present\n# in the set\nmixture.discard(\"something\")<\/pre>\n\n\n\n
A single element can also be removed from a set using the remove<\/strong> method. The difference here is that the remove<\/strong> method will raise an error if the element to be removed is not present in the set.<\/p>\n\n\n\n
# remove \"b\" from set\nmixture.remove(\"b\")\n \n# try to remove \"something\"\n# from set\nmixture.remove(\"something\") # error occurs<\/pre>\n\n\n\n
Sets are mutable<\/strong><\/h2>\n\n\n\n
<\/strong><\/p>\n\n\n\n
Mutable<\/strong> means that an object can be changed after it is instantiated. Thus, if we create a set, we can change its contents without formally re-defining the set. We\u2019ve already seen examples of this above. For example, consider again adding an element to a set.<\/p>\n\n\n\n
# add 60 to nums set\nnums.add(60)\n \n# add 70 to nums set\nnums.add(70)<\/pre>\n\n\n\n
Here, we didn\u2019t have to re-define nums<\/em>. We\u2019re allowed to add an element to the set we\u2019ve already created because of the fact that sets are mutable<\/strong>. If sets were not mutable, we would not be able to do this. To learn more about mutability, see here<\/a>.<\/p>\n\n\n\n
Sets are iterable<\/strong><\/h2>\n\n\n\n
<\/strong><\/p>\n\n\n\n
Sets are also iterable<\/strong>, which means we can loop over the elements of any set.<\/p>\n\n\n\n
test = {4, 5, 6, 7, 8}\n \n# print each element in test\nfor num in test:\n    print(num)<\/pre>\n\n\n\n
Set comprehensions<\/strong><\/h2>\n\n\n\n
Python also supports set comprehensions<\/strong>, which are very similar to list comprhensions<\/a>, except they use sets instead of lists for their base construct. Check out the tutorial on list comprehensions, and you\u2019ll be able to apply the same concepts to set comprehensions.<\/a><\/p>\n\n\n\n
Set comprehensions allow you to create a set by looping through either another set or some other object. For example, below we\u2019re able to create a set where every element is two times the elements in the original set, test<\/em>. This is done my looping through each element in test<\/em> (calling each element here \u201cnum\u201d), and returning num * 2 i.e. the element times two.<\/p>\n\n\n\n
test = {4, 5, 6, 7, 8}\n \n# multiply every element in test by 2\n{num * 2 for num in test}<\/pre>\n\n\n\n
Just like list comprehensions, set comprehensions also support looping and filtering in one step. Below we loop through each element in test<\/em> and output that element to a new set if the element is less than 6 (\u201cnum < 6\u201d).<\/p>\n\n\n\n
# get the subset of test where each number is less than 6\n{num for num in test if num < 6}<\/pre>\n\n\n\n
\"\"<\/figure>\n\n\n\n
Originally posted on TheAutomatic.net<\/a> blog<\/em>.<\/p>\n","protected":false},"excerpt":{"rendered":"
Sets are useful for when dealing with a unique collection of elements \u2013 e.g. finding the unique elements within a list to determine if there are any values which should be present. <\/p>\n","protected":false},"author":388,"featured_media":188169,"comment_status":"closed","ping_status":"closed","sticky":true,"template":"","format":"standard","meta":{"_acf_changed":false,"footnotes":""},"categories":[339,343,349,338,341],"tags":[806,595],"contributors-categories":[13695],"class_list":{"0":"post-187803","1":"post","2":"type-post","3":"status-publish","4":"format-standard","5":"has-post-thumbnail","7":"category-data-science","8":"category-programing-languages","9":"category-python-development","10":"category-ibkr-quant-news","11":"category-quant-development","12":"tag-data-science","13":"tag-python","14":"contributors-categories-theautomatic-net"},"pp_statuses_selecting_workflow":false,"pp_workflow_action":"current","pp_status_selection":"publish","acf":[],"yoast_head":"\nAll about 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